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4 years ago

How do average speed, distance, and time all relate to each other

1 answer:

6 0

Average speed = (total distance covered) / (total time to cover the distance)

Distance = (average speed) x (time to go the distance)

Time to cover the distance = (total distance) / (average speed)

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What’s 5/16 written as a decimal

IgorC [24]

You divide 5 and 16 to get the answer: 0.3125.

4 0

3 years ago

Read 2 more answers

Find the slope of the line whose equation is 8y-16x=12

Mice21 [21]

The formula for slope is y=mx+b
so if you re arrange the equation from 8y-16x=12
to 8y=16x+12
the slope will be the coefficient of x =16

5 0

3 years ago

Solve for t. 4=2+2/5t

maxonik [38]

T=5

4=2+2/5t
Subtract 2 from both sides.
2=2/5t
Multiply both sides by 5/2.
t=5

8 0

3 years ago

Read 2 more answers

A survey of 2500 subscribers to a certain news paper revealed that 2250 people subscribe to the daily morning edition and 1250 s

Aleks04 [339]

1500 people subscribed Sunday edition and 250 people subscribed only sunday edition.

<u>Solution:</u>

Given, A survey of 2500 subscribers to a certain news paper revealed that 2250 people subscribe to the daily morning edition

And 1250 subscribe to both the daily and the sunday editions.

We have to find how many subscribe to the Sunday edition? how many subscribe to the Sunday edition only?

Let x denote the number who subscribe to the Sunday edition.

Then the addition rule with overlap tells us that

Those who subscribe daily edition + those who subscribe sunday edition - those who subscribe both daily and sunday edition = total subscribers in survey

2250 + x – 1250 = 2500

1000 + x = 2500

x = 1500

so, 1500 subscribe to the Sunday edition and 1500 – 1250 = 250 subscribe to the Sunday edition only.

Hence, 1500 people subscribed Sunday edition and 250 people subscribed only sunday edition.

6 0

3 years ago

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

4 years ago