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hammer [34]
3 years ago
9

Write the slope-intercept form of an equation of the line that passes through (-2, 5) and has an undefined slope.

Mathematics
1 answer:
mart [117]3 years ago
6 0

For any given point of the line the x-coordinate is -2. (a vertical line) This means that the equation of the line is

<h2> x=-2</h2>
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Please help due today!
Inessa [10]

Answer:

NO=22.6

Step-by-step explanation:

NO=MO+MN

after substituting MO and MN,

NO=15+7.6

=22.6

also, the problem says to answer with only the number, so just type 22.6!

8 0
3 years ago
Read 2 more answers
Can anyone help me ASAP!
love history [14]

Answer: c 14m

Step-by-step explanation: hope this helped

5 0
2 years ago
Read 2 more answers
Solve for all values of p: ​
Alchen [17]

Answer:

p = - 5, p = - 1

Step-by-step explanation:

Given

\frac{3p}{p-5} - \frac{2}{p+3} = \frac{p}{p+3}

Multiply through by the LCM of (p - 5)(p + 3)

3p(p + 3) - 2(p - 5) = p(p - 5) ← distribute parenthesis

3p² + 9p - 2p + 10 = p² - 5p

3p² + 7p + 10 = p² - 5p ( subtract p² - 5p from both sides )

2p² + 12p + 10 = 0 ← divide through by 2

p² + 6p + 5 = 0 ← in standard form

(p + 1)(p + 5) = 0 ← in factored form

Equate each factor to zero and solve for p

p + 1 = 0 ⇒ p = - 1

p + 5 = 0 ⇒ p = - 5

3 0
2 years ago
The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the tri
son4ous [18]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
11000 is compounded semiannually at a rate of 12% for 21 years. Find the total amount in the compound interest account
marishachu [46]

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad&#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\dotfill &\$11000\\&#10;r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{semiannually, thus twice}&#10;\end{array}\dotfill &2\\&#10;t=years\dotfill &21&#10;\end{cases}


\bf A=11000\left(1+\frac{0.12}{2}\right)^{2\cdot 21}\implies A=11000(1.06)^{42}\implies A\approx 127127.359416

5 0
3 years ago
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