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antiseptic1488 [7]
3 years ago
10

What is 9minus w = to

Mathematics
2 answers:
skad [1K]3 years ago
7 0
9 - w = 2 

9 - 7 = 2

If this is what you mean.
Nataly [62]3 years ago
3 0
9-w would be the simpliest form.

But, if you meant, to= 2, then:

9-w= 2

Subtract 9 on both sides.

-w= -7

Divide by -1, since the w cannot be negative.

w= 7

We can check this by plugging it in.

9-(7)= 2
2=2 <- this works

I hope this helps! Let me know if I need to make any changes.
~kaikers
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Vsevolod [243]
I don’t really know exactly to what degree you need to put in your solution. But I rounded to the nearest tenth degree.
A = 112 degrees
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b= 14 (side opposite b)
c= 19.2 (side opposite c)

HOW TO SOLVE:
c= law of sines, so c/sin(40) = 14/sin(28), multiply both sides by sin(40) so c can be isolated and solved for. c = 14sin(40)/sin(28). Plug into calculator then get answer. c is approximately 19.2.
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7 0
3 years ago
Which of the following describes the behavior of the graph shown over the interval (-2,2)?
sergejj [24]

Hello!

We are trying to describe the behavior of the graph given in the question.

To help us understand how to solve this question, we would need to understand <u>concavity.</u>

There are two types of concavity:

  • Concave <em>up</em>
  • Concave <em>down</em>

When a graph is concave up, the slope of the line would look like a "U".

When a graph is concave down, the slope of the line would look like a "U" that is flipped upside down.

In this case, we can see that the graph is concave down.

We can tell that the <em>slope</em> is negative due to the fact that the slope is going <u>down,</u> which results in the graph having a negative slope.

We can also tell that the graph is decreasing due to the fact that the line is doing downward.

Answer:

C). negative and decreasing

7 0
1 year ago
Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees
lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e.  \mu=0 and \sigma= 1  

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0
3 years ago
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