Solution: As the line shown in the graph passes through (3,0) and (0,-1).
So, equation of line passing through (3,0) and (0,-1) is given by two point formula i.e equation of line passing through (p,q) and (a,b) is given by
→![\frac{y-q}{x-p}=\frac{q-b}{p-a}](https://tex.z-dn.net/?f=%5Cfrac%7By-q%7D%7Bx-p%7D%3D%5Cfrac%7Bq-b%7D%7Bp-a%7D)
→![\frac{y-0}{x-3}=\frac{0+1}{3-0}](https://tex.z-dn.net/?f=%5Cfrac%7By-0%7D%7Bx-3%7D%3D%5Cfrac%7B0%2B1%7D%7B3-0%7D)
So ,the equation of line is ,→3 y = x-3
→ x- 3 y -3= 0 or y=x/3 -1
take point (0,0) and putting in the above equation, we see that ,L.H.S>R.H.S
Similarly if you take other points , like (1,0).(0,1) we see that ,L.H.S>R.H.S.
it means the above equation can be written as , y≥x/3 -1.
None of the option is correct.