ANSWER
The vertex of the graph of

is

EXPLANATION
The vertex form of a parabola is given by

where

is the vertex of the parabola.
The function given to us is

This is already in the vertex form.
When we compare this to the general vertex form, we have,


and

Therefore the vertex of the parabola is

Hence the correct answer is option A.
We have to use the distance formula between the two points provided
Answer:
you can name it a or b like any letters
Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
Answer:
Step-by-step explanation:
Discussion
First draw FH
<FOH and <FGH share the end points of the chord FH
<FOH is a central angle.
<FGH touches the circumference of the circle in the on the same side of the point of angle <FOH is closest to
Therefore <FGH is 1/2 <FOH. That is always true of central angles and the smaller angle touching the circumference that <FOH points to
Conclusion
<FGH = 1/2 < FOH
58 = 1/2 <FOH
Therefore <FOH = 2 * 58 = 116
y = < FOH
Answer
y = 116