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3 years ago

I need the formula an answer to 4+3*5=

Mathematics

1 answer:

nevsk [136]3 years ago

4 0

Answer:

Step-by-step explanation:

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|4x+8|> 2 what is the answer

Nookie1986 [14]

Step-by-step explanation:

|4x + 8| > 2

Therefore 4x + 8 > 2 or 4x + 8 < -2.

When 4x + 8 > 2, 4x > -6, x > -1.5.

When 4x + 8 < -2, 4x < -10, x < -2.5.

Hence, x < -2.5 or x > -1.5.

5 0

3 years ago

Read 2 more answers

|18-x|, if x<18. Pls help

damaskus [11]

Answer:

I18 - xI such that x < 18.

ok, first let's what happens if x = 18:

I18 - xI = I18 - 18I = 0

So, at the moment we have the condition:

I18 - xI > 0.

now, if x is a really large negative number, suppose, x = -100

I18 + 100I = I118I = 118

So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:

I18 - xI > 0.

This means that the domain is:

D = (-∞, 18)

and the range is:

R = (0, ∞)

3 0

3 years ago

On a factory floor, 30 out of every 140 toy robots is defective. What percent is defective?

yaroslaw [1]

Answer:

$21.43\%$

Step-by-step explanation:

we know that

To find out the percent of robots which are defective, divided the number of defective robots by the total number of robots and multiply the result by 100

Let

x ----> the number of defective robots

y ----> the total number of robots

p ---> percentage of robots which are defective

$p=\frac{x}{y} (100)$

we have

$x=30\\y=140$

substitute

$p=\frac{30}{140}(100)$

$p=21.43\%$

5 0

3 years ago

HEELPLPLPLPLPLPLPLPLPLPRDVJNLDFBLJFC,LVDZFBV,JDZFHBXV

olga_2 [115]

You first add up how many erasers there are in the bag so there are 20 and then you check how many purple erasers there are and so there are 5 and so the answer is 5/20 or 1/4 which is 0.25 as a decimal and if you do probability the answer has to be in between o and 1 and so 0.25 is in between 0 and 1 so it should be correct

3 0

3 years ago

Read 2 more answers

Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m

JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment .

A) Determine the test statistic

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5) / $\sqrt{0.5*0.5 / 200}$ = 2.12

b) determine the p-value

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 ) = 1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0

3 years ago