Question

James flips a fair numbered cube with faces numbered 1-6 and flips a quarter what is the probability that in one turn James could roll an odd number and flip a heads on the quarter

Answer 1

Answer:

Therefore the probability that in one turn James could roll an odd number and fip a heads on the quarter is  = $\frac{1}{2}$ × $\frac{1}{2}$ = $\frac{1}{4}$.

Step-by-step explanation:

i) There are three odd numbered faces on the cube, that is the faces having 1, 3, and 5.

Therefore the probability of rolling an odd numbered face is = $\frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{1}{2}$ since the probability of rolling 1 = probability of rolling 3 = probability of rolling 5 = $\frac{1}{6}$

ii) The probability of flipping a head on the quarter = probability of flipping a tail on the quarter = $\frac{1}{2}$

iii) Therefore the probability that in one turn James could roll an odd number and fip a heads on the quarter is  = $\frac{1}{2}$ × $\frac{1}{2}$ = $\frac{1}{4}$