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Contact [7]
3 years ago
12

3m(2m+9)=0 what is the factor of m

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0
3m(2m+9)=0 \\ \\3m=0 \ \ \vee \ \ 2m+9 = 0\\ \\ m=0 \ \ \vee \ \ 2m= -9 /:2\\ \\m=0 \ \ \vee \ \ m= -\frac{9}{2} \\ \\m=0 \ \ \vee \ \ m= -4\frac{1}{2}


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There are 14 girls and 12 boys in a class. What is the ratio of girls to students?
frosja888 [35]

Answer:

7:13

Step-by-step explanation:

There are 14 girls and 12 boys, so there are 26 students in total. Since we are looking for the ratio of girls to students, the ratio will be 14:26. To simplify it, we will divide 14 and 26 by their greatest common factor: 2. We will get the ratio of 7:13.

I hope this helped! :)

6 0
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Suppose $100 is deposited into an account and the amount doubles every 8 years. How much will be in the account in 40 years? (Us
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3 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Greeley [361]

Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

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X₁: penetrability of a plot with compressed soil.

n₁= 20 plots

X[bar]₁= 2.90

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Sample 2: Intermediate soil

X₂: penetrability of a plot with intermediate soil.

n₂= 20 (with outlier) n₂= 19 plots (without outlier)

X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)

S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)

Outlier: 4.26

Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

Parámeter of interest: μ₁-μ₂

Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

5 0
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