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anastassius [24]
3 years ago
5

I need help and i need it fast!

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

15.  14

16. 44

17. 11

18. -56

Step-by-step explanation:

15 . 4 * 7 = 28 divide by 2 = 14

16. 2^3 = 8 * 3 = 24 +5 * 4 = 20 ,  20 + 24 = 44

17. 5 + 4 = 9 + 2 =11

18. 6 * 2 = 12 and -34 * 2 = -68 - 12 = 56

hope this helps mark me brainlist if it did

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(I need the answer right now please) ΔA'B'C' was constructed using ΔABC and line segment EH. 2 triangles are shown. Line E H is
irina1246 [14]

Answer:

The true statements are

1. BD = DB'

3. m∠EFA = 90°

4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and

   CC'

Step-by-step explanation:

* Lets explain how to solve the problem

- Reflection is flipping an object over the line of reflection.

- The object and its image have the same shape and size, but the

  figures are in opposite directions from the line of reflection

- The objects appear as if they are mirror reflections, with right and left

  reversed

- The line of reflection is a perpendicular bisector for all lines joining

  points on the figure with their corresponding images

- Look to the attached figure for more understand

* Lets solve the problem

- ΔA'B'C' was constructed using ΔABC and line segment EH, where

 EH is the reflection line

- D is the mid-point of BB'

- F is the mid-point of AA'

- G is the mid-point of CC'

* Lets find from the answer the true statements

1. BD = DB'

∵ D is the mid point of BB'

- Point D divides BB' into two equal parts

∴ BD = DB' ⇒ <em>True</em>

2. DF = FG

- It depends on the size of the sides and angles of the triangle

∵ We can't prove that

∴ DF = FG ⇒ <em>Not true</em>

3. m∠EFA = 90°

∵ The line of reflection ⊥ the lines joining the points with their

   corresponding images

∴ EH ⊥ AA' and bisect it at F

∴ m∠EFA = 90° ⇒ <em>True</em>

4. The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC'

- Yes the line of reflection is perpendicular bisectors of them

∴ The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC' ⇒ <em>True</em>

5. ΔABC is not congruent to ΔA'B'C'

∵ In reflection the object and its image have the same shape and size

∴ Δ ABC is congruent to Δ A'B'C'

∴ ΔABC is not congruent to ΔA'B'C' ⇒ <em>Not true</em>

4 0
3 years ago
Read 2 more answers
1 2 3 4 5 6 7 8 9 10 TIME REMAINING 54:32 Because the lid of a marker is wider than the marker itself, a set of markers can be p
tia_tia [17]

Answer:

10 Square Inches

Step-by-step explanation:

<u>Trapezoid</u>

Base =12 inches

Height =10 inches

Top side= 10 inches.

Area of a Trapezoid=\frac{1}{2}(a+b)h, $where a and b are the lengths of the base and top respectively$

=\frac{1}{2}(10+12)*10\\=5*22=110 \:Square\:Inches

Area of the Trapezoid=110 Square Inches

<u>Rectangle</u>

Base = 12 inches

Height =10 inches.

Area of a Rectangle=Base X Height

=12 X 10

=120 Square Inches

<u>Difference in Area between the two packages</u>

Difference=Area of Rectangle-Area of Trapezoid

=120-110

=10 Square Inches

5 0
3 years ago
Read 2 more answers
what fraction is equivalent to -3/2? i’m going to keep writing because it has to be 20 words. Anyways thank you if you answer th
Alinara [238K]
A fraction that is equivalent to -3/2 would be -9/6

A great form to prove this is by using a calculator and dividing -9 by 6 this should get you the answer of 1.5!

Hope this helps!
7 0
3 years ago
the graph below shows the relationship between dithering distances a delivery truck is driven and the amount of gas the truck us
LiRa [457]

Answer:

10

Step-by-step explanation:

Look at where the one gallon gas is, it's point comes to ten. :)

4 0
2 years ago
Solve 3x2 + 4x = 2<br>I need it solved with the quadratic formula​
lisabon 2012 [21]
3x2+4x=2
6+4x=2
-6 -6
4x=-4
4 4
x=-1
8 0
3 years ago
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