Question

What is log6^e f rewritten using the power property?

Answer 1

$\bf \textit{Logarithm of exponentials}\\\\ log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\ -------------------------------\\\\ log_6(e^f)\implies flog_6(e)$

Answer 2

Given expression : $log_6e^f .$.

We need to apply power property of logs to rewrite it.

According to log rule of exponents:

$log_b a^n = n log_b(a)$

If we compare given expression with the rule the exponent part is f, base is 6.

Therefore, we need to bring exponent f in front of log.

Therefore, $log_6e^f = flog_6 e$.

And correct option is second option $flog_6 e.$