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KatRina [158]
2 years ago
7

Choose all the options that describe the result of the multiplication

Mathematics
2 answers:
Anna35 [415]2 years ago
7 0
A, B and c are all answers
bezimeni [28]2 years ago
4 0
<h2>Answer:</h2>

Option: c is the correct answer.

         c.  irrational.

<h2>Step-by-step explanation:</h2>

On multiplying the two terms as follows:

\dfrac{4}{3}\times \dfrac{\sqrt{6}}{2}\\\\\\=\dfrac{4\sqrt{6}}{6}\\\\\\=\dfrac{4}{\sqrt{6}}\\\\\\=\dfrac{2\sqrt{2}}{\sqrt{3}}

As we could observe that the result of the multiplication contain a square root term.

Hence, the number is not an integer.

Also, it is not an rational number.

( Since its decimal expansion is non-terminating)

Hence, the answer is: It is an irrational number.

     

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Y=2x-7<br> y=-3x+18 <br> solve by substitution
Liono4ka [1.6K]

Answer:

-x+11

Step-by-step explanation:

am not sure if this is correct but

2x-3x=-x

-7+18=11

-x+11

8 0
2 years ago
Why does it take 3 copies of 1/6 to show the same amount as 1 copy of 1/2? explain your answer
sertanlavr [38]
It takes 3 copies of 1/6 to show the same amount as 1 copy of 1/2 because 3 copies of 1/6 would add up to 3/6 thus making it 1/2 
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3 years ago
NORTH RIDGE MIDDLE SCHOOL collected 5,022 cans of food for food drive. Each of the 18 homerooms collected the same number of can
Diano4ka-milaya [45]

Answer:

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18 estimate= 20

So, 5022/20

=251

Step-by-step explanation:

The questions says "about" so that means you have to estimate. First, you estimate the cans, then, you estimate the homerooms = 5022 and 20. Last, you have to divide, 5022/20

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Hope it helped!:)

4 0
3 years ago
Stretch your thinking, solve the story problem. Draw comparison bars. There were 11 hikers here yesterday. There are 4 hikers he
lara [203]
11-4=7 your welcome
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3 years ago
If A= [-5,7] and B= [6,10], then find A u B
lesantik [10]

Answer:

\large\boxed{A\ \cup\ B=[-5,\ 10]}

Step-by-step explanation:

Look at the picture.

The union of two sets A and B (A ∪ B) is the set of elements which are in A, in B, or in both A and B

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