<h2>
Answer:</h2>
Option: c is the correct answer.
c. irrational.
<h2>
Step-by-step explanation:</h2>
On multiplying the two terms as follows:

As we could observe that the result of the multiplication contain a square root term.
Hence, the number is not an integer.
Also, it is not an rational number.
( Since its decimal expansion is non-terminating)
Hence, the answer is: It is an irrational number.