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Alexxx [7]
3 years ago
15

Martey drew a model of the shool library

Mathematics
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

Q?

Step-by-step explanation:

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Please answer this equation what is the answer to 1/4(k-1)=10
laiz [17]
\frac{1}{4}(k-1)=10^{(4} \\\\ k-1=40 \\\\ k=40+1 \\\\ \boxed{k=41}
8 0
3 years ago
Read 2 more answers
Find the volume of the prism.
ExtremeBDS [4]

Answer:

Its A.

Step-by-step explanation:

remember its rectangle 1 + rectange 2.Once i did that i have seen the total volume must be greater then answer B

so it must be a

6 0
3 years ago
10 + (2 x 3)2 ÷ 4 × 1 over 2 to the power of 3
Zielflug [23.3K]

Answer:

1.4375

Step-by-step explanation:

\frac{10 + (2 x 3)^{2} / (4)(1)}{2^{3}} \\

\frac{10 + (6)^{2} /4}{8} \\

\frac{10 + 36 / 4}{8} \\

\frac{46 /4}{8} \\ = \frac{11.5}{8} \\

7 0
2 years ago
Using the TI-84 calculator, find the area under the standard normal curve. Round the answers to four decimal places.(a) Find the
madam [21]

Answer:

a) 0.705

b) 0.976

c) 0.01

d) 0.09

Step-by-step explanation:

We have to find the area under the standard normal curve.

a) area under the standard normal curve that lies outside the interval between z= −1.98 and z=0.61.

=P(-1.98

b) area under the standard normal curve to the left of z=1.98

=P(z

c) area under the standard normal curve to the right of z= 2.34

P(z>2.34)\\=1 - P(z

d)  area under the standard normal curve that lies between z= −0.94 and z= −0.63

=P(-0.94

6 0
3 years ago
I need help solving this problem
zloy xaker [14]

9514 1404 393

Explanation:

When something is subtracted from both sides of the equation, the justification is the <em>subtraction property of equality</em>. When something multiplies both sides of the equation, the justification is the <em>multiplication property of equality</em>. (This should not be a mystery.)

Here, the equation is solved by subtracting 17/3, then subtracting 1/2x, then multiplying by the inverse of the coefficient of x. After each of these steps is a simplification.

  \begin{array}{cc}\dfrac{17}{3}-\dfrac{3}{4}x=\dfrac{1}{2}x+5&\text{given}\\\\\dfrac{17}{3}-\dfrac{3}{4}x-\dfrac{17}{3}=\dfrac{1}{2}x+5-\dfrac{17}{3}&\text{subtraction property ...}\\\\-\dfrac{3}{4}x=\dfrac{1}{2}x-\dfrac{2}{3}&\text{simplify}\\\\-\dfrac{3}{4}x-\dfrac{1}{2}x=\dfrac{1}{2}x-\dfrac{2}{3}-\dfrac{1}{2}x&\text{subtraction property ...} \end{array}

  \begin{array}{cc}-\dfrac{5}{4}x=-\dfrac{2}{3}&\text{simplify}\\\\-\dfrac{5}{4}x\times-\dfrac{4}{5}=-\dfrac{2}{3}\times-\dfrac{4}{5}&\text{multiplication property ...}\\\\x=\dfrac{8}{15}&\text{simplify} \end{array}

4 0
3 years ago
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