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3 years ago

Image attached. This is geometry and I’m confused.

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

4 0

Answer:

90 degrees

Step-by-step explanation:

angle b is 180-90-56=34 degrees

that means angle c is also 34 degrees.

56+34=90, thus angle BCE is also 90 degrees

maks197457 [2]3 years ago

3 0

Answer:

BCE = 90 degrees

Step-by-step explanation:

We can find the measure of angle ABC because we already know the other two angles, ACB and A, and there are 180 degrees in a triangle. So, we can set up the equation 90 + 56 + B = 180. If we solve this, it comes out to B = 34 degrees. It's given that angle B and ECD are congruent, so ECD also equals 34.

Because line segment DCA is a straight line, angles ECD, BCE, and ACB will add up to 180 degrees, since they make up a straight angle. So, we can set up the equation 34 + 56 + BCE = 180, which solves out to BCE = 90 degrees, so BCE is equal to 90 degrees.

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In 1989, Dutch ice skater Dries van Wijhe skated 200 km at an average speed of 35.27 km/h. How long was he skating?

avanturin [10]

T = d/s

t = 200/35.27

Hope that helps!!!

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2 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

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3 years ago

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Komok [63]

Answer:

hope it helps you plz mark me brilliantest

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the value of x and y

djverab [1.8K]

Answer:

x = 8, y = 27

Step-by-step explanation:

Since both opposite lines are equal in length to each other, these opposite lines are parallel to each other. The top line is parallel and same length as the bottom line and the left and right lines are also parallel and equal in length.

Based on that, the two left side angles must equal 180 and the right side two angles must equal 180.

(2y + 24) + (3y + 21) = 180

That's the same as 2y + 24 + 3y + 21 = 180

Simplify to 5y + 45 = 180

Subtract 45 from both sides

5y = 135

y = 27

(16x - 26) + (9x + 6) = 180

16x - 26 + 9x + 6 = 180

25x - 20 = 180

25x = 200

x = 8

7 0

2 years ago

How you solve this??

FrozenT [24]

I have no idea sorry

4 0

3 years ago