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Eddi Din [679]
3 years ago
7

How many times larger than (8 + 22) is 8 x (8 + 22)?

Mathematics
2 answers:
Reptile [31]3 years ago
7 0

Answer:

8

Step-by-step explanation:

8+22 = 30

In order to solve 8 • (8+22), we'll need to use the order of operations. First, complete what is in parenthesis.

8 • (8+22)

30

Then, multiply 30 by 8.

30 • 8 = 240.

So, you can then divide to find your answer. If you divide 240 by 30, you will find that 8 • (8+22) is 8 times larger than 8+22.

9966 [12]3 years ago
7 0

Answer:

8 times larger

Step-by-step explanation:

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4 years ago
A sculpture is made of solid copper in the shape of a cone. The sculpture is 67 inches tall, and it’s base has a radius of 15 in
alexgriva [62]

Answer:

$16725.21

Step-by-step explanation:

The first thing is to calculate the cone volume, because they give us the value of copper in cubic inches.

We have that the volume of a cone is:

v = pi / 3 * (r ^ 2) * h

we know these values r = 15 and h = 67

v = (3.14 / 3) * (15 ^ 2) * (67)

v = 15778.5

the volume then is 15778.5 cubic inches, now we multiply this value by the price which is $ 1.06 per cubic inch:

c = 15778.5 * 1.06

c = 16725.21

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7 0
3 years ago
Find dy/dt for the equation below.<br><br> 7x^3+2xy+3y^3=3
castortr0y [4]

dy/dt is -\frac{(21x^2+2y)\frac{dx}{dt}}{2x+9y^2}

What is differentiation?

Differentiation is a method of finding the derivative of a function. Differentiation is a process, in mathematics, where we find the instantaneous rate of change in function based on one of its variables. The most common example is the rate change of displacement with respect to time, called velocity.

We can find the dy/dx as shown below:

7x^3+2xy+3y^3=3

differentiating with respect to t.

7\frac{d(x^3)}{dt} +2\frac{d(xy)}{dt}+3\frac{y^3}{dt}=0

7\frac{3x^2dx}{dt}+2y\frac{dx}{dt}+2x\frac{dy}{dt}+3\frac{3y^2dy}{dt}=0

21\frac{x^2dx}{dt}+2y\frac{dx}{dt}+2x\frac{dy}{dt}+9\frac{y^2dy}{dt}=0

(21x^2+2y)\frac{dx}{dt}+(2x+9y^2)\frac{dy}{dt}=0

(21x^2+2y)\frac{dx}{dt}=-(2x+9y^2)\frac{dy}{dt}

-\frac{(21x^2+2y)\frac{dx}{dt}}{2x+9y^2}=\frac{dy}{dt}

\frac{dy}{dt}=-\frac{(21x^2+2y)\frac{dx}{dt}}{2x+9y^2}

Hence, dy/dt is -\frac{(21x^2+2y)\frac{dx}{dt}}{2x+9y^2}

Learn more about differentiations here:

brainly.com/question/25081524

#SPJ1

6 0
2 years ago
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