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Murrr4er [49]
3 years ago
11

Evaluate log3 (8), given log3 (2) ≈ 0.631

Mathematics
1 answer:
IRINA_888 [86]3 years ago
7 0

Answer: 1.893 Welcome

Step-by-step explanation:

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Step-by-step explanation:

65-13=54

54/4=13

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The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.
djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

where,

r_1 = radius of sphere = \frac{Diamtere}{2}=\frac{8cm}{2}=4cm

r_2 = radius of cylindrical wire = \frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

\frac{4}{3}\times r_1^3=r_2^2h

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h=8533.33cm\approx 8533cm

Therefore, the length of the wire is, 8533 cm

6 0
3 years ago
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