If you have a calculator with statistical functions, that's the way to go.
On my TI-83, I typed in invNorm(0.88) and got the result z = 1.17.
88% of the area under the normal curve is to the left of z = 1.17.
Answer:
The y intercept for this one is two.
Answer:
a) E(X) = 71
b) V(X) = 20.59
Sigma = 4.538
Step-by-step explanation:
<em>The question is incomplete:</em>
<em>According to a 2010 study conducted by the Toronto-based social media analytics firm Sysomos, 71% of all tweets get no reaction. That is, these are tweets that are not replied to or retweeted (Sysomos website, January 5, 2015).
</em>
<em>
Suppose we randomly select 100 tweets.
</em>
<em>a) What is the expected number of these tweets with no reaction?
</em>
<em>b) What are the variance and standard deviation for the number of these tweets with no reaction?</em>
This can be modeled with the binomial distribution, with sample size n=100 and p=0.71, as the probability of no reaction for each individual tweet.
The expected number of these tweets with no reaction can be calcualted as the mean of the binomial random variable with these parameters:

The variance for the number of these tweets with no reaction can be calculated as the variance of the binomial distribution:

Then, the standard deviation becomes:

Answer:
Perimeter of the final star = 40 cm²
Step-by-step Explanation:
The perimeter of the six-pointed star is the sum of the sides of the 6 equilateral triangles that form a boundary around the star.
1 triangular tiles gas a perimeter of 10cm.
Only 2 out of the 3 equal sides of each of the 6 equilateral triangles form the boundary of the final star.
Therefore, perimeter of the final star = ⅔ of the total perimeter of 6 triangular tiles
= ⅔ of (10*6)
= ⅔*60
= 2*20
Perimeter of the final star = 40 cm²