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jolli1 [7]
3 years ago
10

Tom bought 20 boxes of flowers. Each box cost him £6. Each box contains 15 flowers. 3/5 He sells of the total number of flowers

for 70p each. He then sells the remaining at 50p each. Work out the total profit Tom makes.
Mathematics
2 answers:
prisoha [69]3 years ago
7 0

Answer:

66

Step-by-step explanation:

The money he spent:

20 x 6 = 120

=> The number of flowers he bought:

=> 15 x 20 = 300

3/5 of 300 = 900/5 = 180

So, he sold 180 flowers for 70cents.

=> 180 x 70 = 12600 cents

=> 126  dollars

The remaining for 50 cents

=> 2/5 x 300 = 600 / 5 = 120

So, he sold 120 flowers for 50 cents

=> 120 x 50 = 6000 cents

=> 60 dollars

He got a total of 60 + 126 = 186 dollars.

He spent 120 dollars in the starting to buy the flowers.

=> 186 - 120

=> 66 dollars

So, he gets a profit of 66 dollars.

Bond [772]3 years ago
3 0

330

20 * 6 equals 120 that is the cost price

and 3/5 of the 15 flowers is 9 which was sold for 7

and the remaining that is 15 - 9 that's 6 sold for 50 each

now times it by 70 * 9 equals 630 50 * 6 equals 300 so 630 - 300 equals to 330 that is the profit

I hope this helps

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The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

7 0
3 years ago
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