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LUCKY_DIMON [66]
3 years ago
10

Each circle has center O. The radius of the smaller circle is 2 and the radius of the larger circle is 6. If a point is selected

at random from the larger circular region, what is the probability that the point will lie in the shaded region
Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

7

Step-by-step explanation:

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What is the value of the expression k – 14 when k = –17?
Vedmedyk [2.9K]
I hope this helps you




-14+?= -17


?= -17+14


?= -3
6 0
3 years ago
Use​ Gauss's approach to find the following sums​ (do not use​ formulas). 1+3+5+7+...999
muminat
S=1+3+5+\cdots+995+997+999
S=999+997+995+\cdots+5+3+1
\implies 2S=(1+999)+(3+997)+(5+995)+\cdots+(995+5)+(997+3)+(999+1)

2S=\underbrace{1000+1000+\cdots+1000+1000}_{500\text{ times}}

(We are adding 500 instances of 1000 because that's how many odd numbers there are between 1 and 1000, inclusive.)

2S=500\times1000=500000
\implies S=250000
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3 years ago
Solve for r. 0.5(r+2.75) = 3
nirvana33 [79]

Answer:

r=3.25

Step-by-step explanation:

5 0
3 years ago
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a photo album contains small and large photographs. Each large photograph has side lengths that are twice the side lengths of ea
zysi [14]
Take the area of the small photograph and divide it by four, assuming it's a square, each side would then be 6 inches. The large photograph has double the side length of the small one, so 6 multiplied by 2 is 12. To find the area of the large (square) photograph, multiply 12 by 12 as two of the sides, and the area of the large photo is 144 square inches
4 0
3 years ago
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Please help! Will give brainliest! Trig ratio!
DiKsa [7]
Good question!

First of all, you need to be aware of the following trigonometrical ratios\functions:

For angle A:

adjacent=12
opposite=35
hypotenuse=37

Hence:
cos(A)= \frac{12}{37} 
\\~\\
sin(A)= \frac{35}{37} 
\\~\\
tan(A)= \frac{35}{12}

I hope that helps!



I am with you if you faced any difficulties!


 


4 0
3 years ago
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