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LUCKY_DIMON [66]
3 years ago
10

Each circle has center O. The radius of the smaller circle is 2 and the radius of the larger circle is 6. If a point is selected

at random from the larger circular region, what is the probability that the point will lie in the shaded region
Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

7

Step-by-step explanation:

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76,80,88,95,100,101,?<br><br> Which number comes next in this sequence?
ANTONII [103]

Answer:

112

Step-by-step explanation:

76->88->100->112

3 0
3 years ago
Read 2 more answers
What percent of 60 is 15
ozzi
Well we know that 
15/60 can be reduced to 1/4 
And 1/4 can be turned into a percent as 25% 

So your answer is 25% 

Good Luck! :)
3 0
2 years ago
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You know that the battery in your alarm clock is going to run out of power soon. If it runs out within the next 24 hours, what i
aivan3 [116]
The probability of an event is given by the number of favorable outcomes divided by the total number of outcomes. Here the event is the alarm clock running out of power. There are 24 hours during which the power can go out. You are asleep during 8 of these. A "favorable" outcome in this case is the power going out while you are sleeping -- that is, during one of those 8 hours. This makes the probability that the power goes out while you are sleeping 8/24.
3 0
3 years ago
A = πηγ2<br> What do you divide by?
defon

Answer:

76.20+q; 76.60Es

Step-by-step explanation:

5 0
2 years ago
According to a recent​ publication, the mean price of new mobile homes is ​$63 comma 800. Assume a standard deviation of ​$7900.
wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,580​, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,117​, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}

For n=25 we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117

4 0
3 years ago
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