A
Step-by-step explanation:First, subtract
2
π
r
2
from each side of the equation to isolate the
h
term:
S
−
2
π
r
2
=
2
π
r
h
+
2
π
r
2
−
2
π
r
2
S
−
2
π
r
2
=
2
π
r
h
+
0
S
−
2
π
r
2
=
2
π
r
h
Now, divide each side of the equation by
2
π
r
to solve for
h
:
S
−
2
π
r
2
2
π
r
=
2
π
r
h
2
π
r
S
−
2
π
r
2
2
π
r
=
2
π
r
h
2
π
r
S
−
2
π
r
2
2
π
r
=
h
h
=
S
−
2
π
r
2
2
π
r
Or
h
=
S
2
π
r
−
2
π
r
2
2
π
r
h
=
S
2
π
r
−
2
π
r
2
2
π
r
h
=
S
2
π
r
−
r
2
r
h
=
S
2
π
r
−
r
Sin= p/h , cos= b/h , tan= p/b
Answer:
55
Step-by-step explanation:
The Distance between (-2, -5) and (-2, 6) is 11 and the distance between (-2, 5) and (3, 5) [the altitiude] is 5. 11 x 5 is 55 so therefore the area is 55 :)
Answer:
1. 343
2. 64
3. 81
4. 12.25
Step-by-step explanation:
The value of x is ![5\sqrt[3]{25}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B25%7D)
.
Solution:
Given expression is ![-7=8-3 \sqrt[5]{x^{3}}](https://tex.z-dn.net/?f=-7%3D8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D)
.
Switch both sides.
![8-3 \sqrt[5]{x^{3}}=-7](https://tex.z-dn.net/?f=8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-7)
Subtract 8 from both side of the equation.
![8-3 \sqrt[5]{x^{3}}-8=-7-8](https://tex.z-dn.net/?f=8-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D-8%3D-7-8)
![-3 \sqrt[5]{x^{3}}=-15](https://tex.z-dn.net/?f=-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-15)
Divide by –3 on both side of the equation.
![$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}](https://tex.z-dn.net/?f=%24%5Cfrac%7B-3%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%7D%7B-3%7D%20%3D%5Cfrac%7B-15%7D%7B-3%7D)
![\sqrt[5]{x^{3}}=-5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%3D-5)
To cancel the cube root, raise the power 5 on both sides.
![(\sqrt[5]{x^{3}})^5=(-5)^5](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%29%5E5%3D%28-5%29%5E5)
To find the value of x, take square root on both sides.
![\sqrt[3]{x^3}=\sqrt[3]{25}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%3D%5Csqrt%5B3%5D%7B25%7D)
![x=5\sqrt[3]{25}](https://tex.z-dn.net/?f=x%3D5%5Csqrt%5B3%5D%7B25%7D)
Hence the value of x is .
