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3 years ago

I’m confused on how to do this, can I get some help?

Mathematics

2 answers:

Sphinxa [80]3 years ago

8 0

Area of a prism = area of base times length

Area of triangle (base) is bh/2 so (9*6)/2

Area of triangle is 27in squared

Then multiply this by the length of the prism (10in)

So 27 * 10 = 270in

The answer is 270in cubed

Murljashka [212]3 years ago

5 0

Answer:

the volume is 540

Step-by-step explanation:

Well it easy, all you have to do is Length* width* height=n

so just follow that and you will get your answer :)

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Solve 2(4a-3)=-2maths<br>

astra-53 [7]

Answer:

bro try by your self

Step-by-step explanation:

and don't forget to follow me ok bro

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3 years ago

PWEASE HELP ME THIS IS A STRUGGLE FOR ME

arlik [135]

I’m pretty sure it’s 56

8 0

3 years ago

Read 2 more answers

Three times a number plus twice another is 10, while their sum is 10, Find the numbers

Aleks [24]

$3a+2b=10 \\\\ a+b=10 \\\\ \boxed{a=10-b} \\\\ 3(10-b)+2b=10 \\\\ 30-3b+b=10 \\\\ -b=10-30 \\\\ -b=-20 \\\\ \boxed{b=20} \\\\ a=10-20 \\\\ \boxed{a=-10}$

5 0

4 years ago

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

4 years ago

Write the equation of the line:<br> SLOPE - 1<br> Y-INTERCEPT - -2

Ierofanga [76]

Answer:

y = 1x - 2

Step-by-step explanation:

thank me later

3 0

3 years ago