The perimeter of a rectangle is 524 m. The length is 42 m greater than the width. what is the length of the rectangle
1 answer:
Let the width be x
Width = x
Lenght = 42 + x
Perimeter of a rectangle = (2 x width) + (2 x lenght)
524 = (2x) + [2(42 + x)]
524 = 2x + 84 + 2x
440 = 4x
110 = x
Width = 110
Length = 42 + 110 = 152
You might be interested in
Y=1.5 at the midpoint of GH. To do this you add the y values of the endpoints together and divide by two ----> 5-2= 3 ----> 3/2= 1.5
Hope this helps you !!
Answer:6.05cm
Step-by-step explanation:
Circumference=2×π×r
38=2×22/7×r
38×7=2×22×r
266=44r
r=266/44
r=6.05cm
let the width of the rectangle be x
area of rectangle is l*b
x * (x + 6) = 40^2
x^2 + 6x = 40^2
x^2 + 6x = 1600
x + 6x =√1600
x + 6x = 40
7x = 40
x = 5.7
Hope you found this useful
Answer:
is this required answer
Step-by-step explanation:
AB=3x-2
=3*8-2
=22
