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avanturin [10]
3 years ago
12

Solve the equation 4s=112

Mathematics
2 answers:
mixer [17]3 years ago
8 0

Answer:

28

Step-by-step explanation:

Divide by 4 and get s=28

algol [13]3 years ago
7 0

Answer:

s=28

Step-by-step explanation:

To do this, we need to isolate s.

We can do this by dividing both sides of the equation by 4.

This will reverse the multiplication being done to s.

Our equation will now be s=28

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sveticcg [70]

Answer: y = 3x

Step-by-step explanation:

The answer is y=3x because every month Giorgio learns a new song. so for the first month they learned 3 songs and in the second month they learn 3 more that adds up to 6 song total, so if you just times the month by 3 you will get your answer.

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2 years ago
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Answer:

someone was already answering it so there it is below

6 1/6

Step-by-step explanation:

(9-3)+(7/15-3/10)

subtract the numbers

6+(7/15-3/10)

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6 1/6

3 0
2 years ago
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What is the range of the function f(x) = 3x2 + 6x - 8?
V125BC [204]

Answer:

  {y | y ≥ -11 }

Step-by-step explanation:

To answer a question like this, it is often helpful to graph the function or to rewrite it to vertex form.

  f(x) = 3x^2 +6x -8

  f(x) = 3(x^2 +2x) -8 . . . . factor the leading coefficient from x terms

  f(x) = 3(x^2 +2x +1) -8 -3(1) . . . . complete the square*

  f(x) = 3(x +1)^2 -11

The form of this equation tells you that the graph is a parabola that opens upward. Its vertex is (-1, -11), so the minimum value is -11. The range is the vertical extent of the function values, so goes upward from -11:

  y ≥ -11

_____

* Vertex form is ...

  f(x) = a(x -h)^2 +k

where "a" is the vertical scale factor and (h, k) is the vertex. When "a" is positive, the parabola opens upward; when it is negative, the parabola opens downward.

The square is completed by adding the square of half the x-coefficient inside parentheses, and subtracting the equivalent amount outside parentheses. Here, we had 2x inside parentheses, so we added (2/2)^2 = 1 inside and -3(1) outside, because "a" was 3.

_____

Brainly provides tools for properly rendering math symbols. 2-11 is not the same as ≥-11.

7 0
3 years ago
For any perfect square trinomial (quadratic), the constant term (last term) must be positive.
Ronch [10]

Answer:

For the perfect square trinomial (quadratic) i.e. \left(x\:+\:3\right)^2, the constant term (last term) is positive.

Step-by-step explanation:

"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.

For example:

\left(x\:+\:3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2

a=x,\:\:b=3

=x^2+2x\cdot \:3+3^2

=x^2+6x+9

Therefore, for the perfect square trinomial (quadratic) i.e. \left(x\:+\:3\right)^2, the constant term (last term) is positive.

5 0
3 years ago
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