Which classification best represnts a triangle with side lengths 10in 12in and 15in
2 answers:
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Given a = 3 and b = - 8 ,
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152
Answer:
4 adult dinosaurs and 12 baby dinosaurs.
Step-by-step explanation:
Let the number of adult dinosaurs be x.
Number of baby dinosaurs = 3x
Number of paintings made by each baby dinosaur = 15
Number of paintings made by each adult dinosaur = 7
Total number of paintings made by 3x baby dinosaurs = Number of baby dinosaurs * Number of paintings made by each baby dinosaur
= 3x * 15
= 45x
Total number of paintings made by x adult dinosaurs = Number of adult dinosaurs * Number of paintings made by each adult dinosaur
= x * 7
= 7x
Total number of paintings made by both baby and adult dinosaurs = 45x + 7x
= 52 x
Again the problem says that the total number of paintings made = 208
So, 52x = 208
Dividing both sides by 52
=
Cancelling out the 52's from the top and bottom on the left
x = 4
So, number of adult dinosaurs = 4
Number of baby dinosaurs = 3x = 3*4 = 12