All categories

3 years ago

Rectangle QRST with vertices Q(-3,2), R(-1,4), S(2,1), and T(0,-1)) in the x-axis

Mathematics

1 answer:

charle [14.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Find the inverse of the function:<br>f(x) = 3x + 6<br>

natta225 [31]

Answer:

x = -2

Step-by-step explanation:

Pull out like factors :

-3x - 6 = -3 • (x + 2)

Solve : -3 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solve : x+2 = 0

Subtract 2 from both sides of the equation :

x = -2

4 0

3 years ago

The distances of a port from 20 differ- ent locations form an AP. If the farthest distance is 300 km, and the nearest distance i

Mkey [24]

Answer:

Required difference = 270/19 km

Step-by-step explanation:

If we consider the AP of distances to be

a, a + r, a + 2r, ..., a + 19r,

where a is the distance of the nearest location from the port and r is the difference between any two successive location.

Given that,

a + 19r = 300 .....(1)

a = 30 ..... (2)

Using (2), from (1), we get

30 + 19r = 300

or, 19r = 300 - 30

or, 19r = 270

or, r = 270/19

Therefore the distance between any two successive location is 270/19 km.

5 0

3 years ago

Brielle excersise for 3/4 hour each day for 6days in arow.altogether,how many hours does she excersise during 6 days?

Simora [160]

12 hours during 6 daya

8 0

3 years ago

A spider ate 25% more bugs this month then last month the spider ate 8 bugs last month

Ierofanga [76]

In this month spider ate 10 bugs.

Step-by-step explanation:

Given,

The spider ate 25% more bugs than last month.

It ate 8 bugs in last month.

To find the number of bugs it ate this month.

<u>Solution</u>

It ate more bugs = 8×25%

=8× $\frac{25}{100}$ = 2

In this month it ate = 8+2 = 10 bugs.

7 0

3 years ago

Read 2 more answers

A hypothetical square grows so that the length of it's diagonals are increasing at a rate of 8 m/min. How fast is the area of th

guapka [62]

Answer:

32 $m^{2}/min$

Step-by-step explanation:

We let the length of the square be l, the diagonal be z and the area be A.

Then by Pythagoras theorem;

$l^{2}+l^{2}=z^{2}\\2l^{2}=z^{2}$

The are of a square of length l is given as;

$A=l^{2}$

Combining these two equations yields;

$z^{2}=2A$

$A=\frac{z^{2} }{2}$

Next, we have been given;

$\frac{dz}{dt}=8$

We are required to find;

$\frac{dA}{dt}$ when z = 4

By chain rule;

$\frac{dA}{dt}=\frac{dA}{dz}*\frac{dz}{dt}$

Differentiating $A=\frac{z^{2} }{2}$ with respect to z yields;

$\frac{dA}{dz}=z$

Therefore,

$\frac{dA}{dt}=\frac{dA}{dz}*\frac{dz}{dt}$ = 8z

When z is 4m the area of the square will be increasing at a rate of;

8m/min * 4m = 32 $m^{2}/min$

5 0

3 years ago