The slower one walks at a rate of 2.2 mi/h, and the faster one walks at a rate of 3.3 mi/h
<h3>
How to find the rate of the hikers?</h3>
The given information is the following:
- The distance between the hikers is 33 miles.
- They meet in 6 hours.
- One of them walks 1.1 miles per hour faster than the other.
If we define x as the rate of the slower one and y as the rate of the faster one, then we can write the equation:
(x + y)*6h = 33mi
And now we can write:
y = x + 1.1mi/h
Replacing that we get the linear equation:
(x + x + 1.1mi/h)*6h = 33mi
(2x + 1.1mi/h)*6h = 33mi
(2x + 1.1 mi/h) = 33mi/6h = 5.5mi/h
2x = 5.5mi/h - 1.1mi/h = 4.4mi/h
x = (4.4mi/h)/2 = 2.2 mi/h
The slower one walks at a rate of 2.2 mi/h, and the faster one walks at a rate of 3.3 mi/h.
If you want to learn more about linear equations:
brainly.com/question/1884491
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Car 4's speed is double Car 2. so you could say "Car 4 doubled by Car 4."
Answer:
f = - 2.7
Step-by-step explanation:
15 + 10f = -12
10f = -12 - 15
f = -27/10
f = - 2.7
So what I personally would do is try and isolate x by itself! I hate working with fractions, as someone with dyscalculia, so I tend to turn those into decimals, but make sure to check with your teacher because they may not want you to do that (you’ll come into rounding issues and a whole thing with sigfigs which won’t pop up for you until high school chemistry/mathematics.)
Move one of those x’s to the other side, and then get it alone by moving the other “number” without the x! IE Move 2/3 over, then add 2 to the 4 on the other side. I THINK you use the flip of 2/3 when you move it over- but don’t quote me! I’d double check with your notes or teacher on the fractions, I despise them and typically work with decimals in my physics class. I hope I helped a little. :)