A)
x=sales
4/100 x + 400≥460
b)
Solve the inequation:
4/100 x+400≥460
lest common multiple= 100
4x+40000≥46000
4x≥46000-40000
4x≥6000
x≥6000/4
x≥1500
answer: the minimun amount tha se will needs to sell is $1500.
B(5,1) I’m smart and don’t worry the answer is correct
3.70+1.25+1.48= 6.43.
20-6.43=13.57
You would get $13.57
4x (2x-3) (x+2) would be your answer.
Answer:
B
Step-by-step explanation:
Where f(x) and g(x) intersect on the x- axis the value of y is zero
Equate either of the 2 functions to 0 and solve for x
Using f(x) = 8x² - 2, then
8x² - 2 = 0 ( add 2 to both sides )
8x² = 2 ( divide both sides by 8 )
x² =
= 
Take the square root of both sides
x = ±
= ± 
Hence k =
→ B