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Fofino [41]
3 years ago
6

Write these expressions as simply as possible

Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0
So it is asking you to group like term so
x terms can be grouped/added/subtracted to other x terms, but not to x^2 or x^3 terms
x^2 terms to x^2 and so on so

1.  9-3k+5k=
9+(5k-3k)=
9+2k

2.  k^2+2k+4k=
k^2+(2k+4k)=
k^2+6k=
Archy [21]3 years ago
4 0
1)\ 9-3k+5k=9+2k\\\\2)\ k^2+2k+4k=k^2+6k=k(k+6)
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A deep sea diver started at sea level (0 feet) and dove at a rate of 5.6 feet per minute. If the diver dove for ½ hour, what rat
Leona [35]

Given:

A deep sea diver started at sea level (0 feet).

Rate of diving = 5.6 feet per minute.

Time = \dfrac{1}{2} hour

To find:

The rational number that represents his position relative to sea level.

Solution:

We know that,

1 hour = 60 minutes

\dfrac{1}{2} hour = 30 minutes

A deep sea diver, dove at a rate of 5.6 feet per minute.

Distance covered in 1 minute = 5.6 feet

Distance covered in 30 minute = 30 × 5.6 feet

                                                    = 168 feet

The diver dove 168 feet in \dfrac{1}{2} hour. Since it is below the sea level, therefore it should be negative.

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Therefore, the correct option is D.

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3 years ago
Reflect shape A in the line x=-1
natulia [17]

Answer:

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Which expression is equivalent to 64x^3-343
In-s [12.5K]

Answer:

B:  (4x - 7)(16x^2 + 28x + 49)

Step-by-step explanation:

64x^3-343 can be rewritten as 4^3x^3 - 7^3 or (4x)^3 - 7^3.  This is the difference of two cubes.  The appropriate formula for factoring such is

       a^3 - b^3 = (a - b)(a^2 + ab + b^2).  Therefore,

our (4x)^3 - 7^3 = (4x - 7)(16x^2 + 28x + 49).  This is Answer B.

4 0
3 years ago
Evaluate the expressions when x = 10 &amp; y =8.<br><br> 2y
klasskru [66]

Answer: 64

Step-by-step explanation:

y=8

plug in 8 for y

2(8)=64

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2 years ago
Indicate all possible values for the variable in each of the expressions: sqrt(2x+2)+sqrt(6-4x)
IrinaK [193]

Answer:

<u>Given expression:</u>

  • \sqrt{2x+2}+\sqrt{6-4x}

<u>The first root is valid when:</u>

  • 2x + 2 ≥ 0 ⇒ 2x ≥ - 2 ⇒ x ≥ - 1

<u>The second root is valid when:</u>

  • 6 - 4x ≥ 0 ⇒ 4x ≤ 6 ⇒ x ≤ 1.5

<u>So the variable x can get values within interval:</u>

  • -1 ≤ x ≤ 1.5 or
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2 years ago
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