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3 years ago

A school principal wants to find out if his school needs more bike racks. A survey is taken of 30 students who

1 answer:

3 0

Answer: This sample may be biased because he is only asking the bike riders when in reality there might be a majority of students who instead take an alternate form of transportation

Step-by-step explanation:

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Find the number if:

Paraphin [41]

Answer:

162 and $\frac{5}{2}$

Step-by-step explanation:

To find the original number multiply by the reciprocal of the multiplier, that is

90 × $\frac{9}{5}$ = $\frac{810}{5}$ = 162

------------------------------------------------------------------------

Similarly

Change the mixed number into an improper fraction

5 $\frac{5}{6}$ = $\frac{35}{6}$ , then

$\frac{35}{6}$ × $\frac{3}{7}$ ( cancel 35 and 7 by 7 / cancel 6 and 3 by 3 )

= $\frac{5}{2}$ × $\frac{1}{1}$

= $\frac{5}{2}$

7 0

3 years ago

Read 2 more answers

F(x) = 3x -6 What is 7 times f(x)

Alina [70]

Answer:

21x - 42, see below :)

Step-by-step explanation:

Hello!

We know that f(x) is equal to 3x - 6

We want to know what 7 * f(x) is so we should first substitute f(x) for 3x - 6

7 * f(x)

7(3x-6)

We use distributive property to open the parenthesis:

7 * 3x + 7 * -6

21x - 42

8 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!!

Zielflug [23.3K]

Question #1

Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.

Part B:
$\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}$
The slope is 22.

Part C:
y = mx + b
y = 22x + 5

We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10

The domain is 10.

Question #2

Part A:

(2,255)
(5,480)

Standard form is Ax + By = C

$\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}$

Let's plug this into this form first:
$y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55$

Now, let's make it into Standard Form.
$y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}$
What, which is in the box, is your final answer. :)

Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
$\boxed{f(x) = 85x + 55}$

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)

5 0

3 years ago

Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. What is the volume of the display box? Explain your

Black_prince [1.1K]

Answer:

$\text{Volume of display box}=216\text{ in}^3$

Step-by-step explanation:

We have been given that Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. We are asked to find the volume of display box.

We know that the box is in form of cuboid, so its volume would be length times width times height.

$\text{Volume of display box}=6\text{ in}\times 9\text{ in}\times 4\text{ in}$

$\text{Volume of display box}=216\text{ in}^3$

Therefore, the volume of the display box is 216 cubic inches.

7 0

3 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago