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3 years ago

Which education and qualifications are most helpful for Law Enforcement Services careers? Check all that apply.

Computers and Technology

1 answer:

bixtya [17]3 years ago

3 0

Explanation:

For IAS..we need a high amptual amount of knowledge..

For IPS..we need master degree and physical fitness too..

For An Advocate..we need Master degree and social Skills..

so..the education and qualifications depends on the various jobs..

HOPE THE ANSWER IS USEFUL

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A screen saver is best described as a

sashaice [31]

A wallpaper or background.

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3 years ago

Which of the following is not a valid variable name? 2 myInt 2. return 3. myInteger 4. total3

Reptile [31]

Answer:

Correct answer is option (2) that is "return".

Explanation:

In any programming language, a variable name can be made up of letters (lower and upper case) and digits. we can also use "_" underscore character for declaring the variables but we cannot use any special character like “$”.We cannot use digits in the beginning of variables name. And we also cannot use reserved keywords of the language like "new","return","while" etc. There should not be space between the variable names. Options 1, 3 and 4 are not violating any of these properties. But in option (2), "return" is a reserved keyword. That is why it is not a valid variable name.

Some example of valid variables name:

foo

BAZ

Bar

_foo42

foo_bar

Some example of invalid variables name:

$foo ($ not allowed)

while ( keywords )

2foo (started with digit)

my foo (spaces )

5 0

4 years ago

Input an int between 0 and 100 and print the numbers between it and 100, including the number itself and the number 100. If the

Murrr4er [49]

import java.util.Scanner;

public class JavaApplication42 {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

int count = 0;

System.out.println("Enter an integer between 0 and 100");

int num = scan.nextInt();

if (num <= 0 || num >= 100){

System.out.println("error");

}

else{

while(num <= 100){

if (count == 20){

System.out.println("");

count = 0;

}

else{

System.out.print(num+" ");

count++;

num++;

}

I hope this helps!

6 0

3 years ago

Consider the code below. Note that the catch statements in the code are not implemented, but you will not need those details. As

Dmitriy789 [7]

Missing Part of Question

An exception raised by the instruction in i3 would be caught by the catch statement labeled?

Answer:

e3 and e4.

Explanation:

The instruction tag i3 points to the following code segment

a[++i] = (double) (1 / x); // i3

The code segment above performs arithmetic operation (double)(1/x)

And then assigns the value of the arithmetic operations to an array element a[++I]

It's possible to have one or both of the following two exceptions.

1. Error in Arithmetic Operation

2. Index of Array out of bound

These are both represented in exception tags e3 and e4

catch (ArithmeticException ex) {...} // e3

catch (ArrayIndexOutOfBounds ex) {...} // e4

Exception e3 can arise when the program try to carry out invalid arithmetic operation.

For instance, 1/0 or 0/0.

This will lead to ArithmeticException to be thrown

Exception e4 can arise when the program tries to assign values to an index that's not in an array.

Say, the total index in a given array a is 5.

The index of this array is 0 to 4; i.e. a[0] to a[4]

The moment the program tries to assign values to array element other than the ones I listed above (e.g a[5]) ArrayIndexOutOfBounds exception will be thrown

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3 years ago

You can align controls in the report design window using the align button on the report design tools ____ tab.

Iteru [2.4K]

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3 years ago