36m^2 is the your answer hope it help
Step-by-step explanation:
x = -10, y = 10
y= -4x+4
m1×m2 = -1
-4 × m2 = -1
m2 = 1/4
y-y1 = m(x-x1)
y-10 = 1/4(x+10)
y-10 = 1/4x +10/4
(×4)
4y-40=x+10
4y=x+50
x-4y+50=0
Answer:
95
Step-by-step explanation:
(8)(10)+6−27+(5)(8)−4
=80+6−27+(5)(8)−4
=86−27+(5)(8)−4
=59+(5)(8)−4
=59+40−4
=99−4
=95
hope this helped :)
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
