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son4ous [18]
3 years ago
5

Two models of cellular telephones, red and blue, are stored in boxes. One box weighs twelve pounds and contains four of the red

models and one blue model. Another box weighs eight pounds and contains one blue model and two red models. How much does each model weigh?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0
First, make a equation in which r= red and b=blue.

So, since in the first box it has 4 red models and one blue model equaling 12,

the first equation looks like 4r+b=12.

The second equation looks like 2r+b=8.

What you would do is try and first solve for r by getting rid of b.

Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.

-1*(2r+b=8)= -2r-b=-8

Add.

4r+b=12
+(-2r-b=-8)

2r=4
r=2

Then, you plug in 2 for the r for any of the original equations.

4(2)+b=12

8+b=12

b=4

or

2(2)+b=8

4+b=8
b=4

So, the red models weigh 2 pounds while the blue models weigh 4.



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C

Step-by-step explanation:

Given

\frac{x}{x^2+3x+2} + \frac{3}{x+1} ← factor the denominator of first fraction

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6.1.3
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Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

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The distribution of these z-variates is known as the standard normal distribution.

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8 0
3 years ago
1. What are the first five terms of the sequence given by the formula an = 5n + 1?
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The correct answers are:

(1) 6, 11, 16, 21, 26 (Option B)

(2)~a_1 = 8; ~a_n = a_{n-1} - 2~ (Option A)

(3)~a_n = -2 + 3(n-1)~~~~ (Option D)

Explanations:

(1) Given Sequence:

a_n = 5n + 1

Now in order to find the first 5 terms, we need to put n=1,2,3,4,5 in the above sequence and solve.

For n=1: a_1 = 5(1) + 1 = 6

For n=2: a_2 = 5(2) + 1 = 11

For n=3: a_3 = 5(3) + 1 = 16

For n=4: a_4 = 5(4) + 1 = 21

For n=5: a_5 = 5(5) + 1 = 26

Hence, the first five terms are: 6, 11, 16, 21, 26 (Option B)

(2) Given Sequence:

8, 6, 4, 2, …

Now to find the recursive definition, we need to adopt trial-and-error approach.

As, a_1 = 8 (meaning the first element of the sequence is 8), the second or nth value of the sequence can be found by using the following formula:

a_n = a_{n-1} - d --- (1)

Where, n = the index of the number in a sequence

d = difference between two consecutive numbers = 8-6 = 2

Now,

The second number of the sequence has to be 6 by using (1). Put n = 2 and d = 2 in (1):

a_2 = a_{2-1} - 2

a_2 = a_{1} - 2

Since a_1 = 8, therefore,

a_2 = 8 - 2 = 6 (correct)

Hence the correct answer is a_1 = 8; ~a_n = a_{n-1} - 2~ (Option A)

(3) Given Sequence:

−2, 1, 4, 7, …

To find the explicit definition, use the following formula:

a_n = a_1 + (n-1)*d --- (X)

Where,

a_n = nth~term~of~the~sequence \\a_1 = 1st~term~of~the~sequence = -2 \\d = common~difference = 4-1 = 7-4 = 3 \\n = index~of~a~number~in~a~sequence \\

Plug in the values in (X):

(X)=> a_n = -2 + (n-1)*3~~~~ (Option D)

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