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son4ous [18]
3 years ago
5

Two models of cellular telephones, red and blue, are stored in boxes. One box weighs twelve pounds and contains four of the red

models and one blue model. Another box weighs eight pounds and contains one blue model and two red models. How much does each model weigh?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0
First, make a equation in which r= red and b=blue.

So, since in the first box it has 4 red models and one blue model equaling 12,

the first equation looks like 4r+b=12.

The second equation looks like 2r+b=8.

What you would do is try and first solve for r by getting rid of b.

Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.

-1*(2r+b=8)= -2r-b=-8

Add.

4r+b=12
+(-2r-b=-8)

2r=4
r=2

Then, you plug in 2 for the r for any of the original equations.

4(2)+b=12

8+b=12

b=4

or

2(2)+b=8

4+b=8
b=4

So, the red models weigh 2 pounds while the blue models weigh 4.



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A friend makes three pancakes for breakfast. One of the pancakes is burned on both sides, one is burned on only one side, and th
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Answer:

50%

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vampirchik [111]

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8 0
3 years ago
A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded
Crank

Answer:

A=81(\pi-1)\ in^2

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

A=\pi r^{2}

we have

r=18/2=9\ in ---> the radius is half the diameter

substitute

A=\pi (9)^{2}\\A=81\pi\ in^2

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

D^2=2b^2

where

b is the length side of the square

we have

D=18\ in

substitute

18^2=2b^2

solve for b^2

b^2=162\ in^2 -----> is the area of the square

Divide by 2

162/2=81\ in^2

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The  area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

A=(81\pi-81)\ in^2

simplify

A=81(\pi-1)\ in^2

8 0
3 years ago
Different dealers may sell the same car for different prices. The sale prices for a particular car are normally distributed with
Stels [109]

Answer:

P(X > 25) = 0.69

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The sale prices for a particular car are normally distributed with a mean and standard deviation of 26 thousand dollars and 2 thousand dollars, respectively.

This means that \mu = 26, \sigma = 2

Find P(X>25)

This is 1 subtracted by the pvalue of Z when X = 25. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 26}{2}

Z = -0.5

Z = -0.5 has a pvalue of 0.31

1 - 0.31 = 0.69.

So

P(X > 25) = 0.69

4 0
3 years ago
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