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AleksAgata [21]
4 years ago
13

A cereal box has dimensions of 2 in., 5 1/3 in., 10 3/4 in.

Mathematics
2 answers:
vekshin14 years ago
8 0
A. Volume = 2 * 16/3 * 43/4

b. Each serving : Volume / 8
gayaneshka [121]4 years ago
5 0
<span>Given: 
A cereal box has dimensions of 2 in., 5 1/3 in., 10 3/4 in.

Volume = length * width * height

First, we convert each value into improper fractions.

2 in. </span>→ 2/1 in
5 1/3 in → 16/3 in
10 3/4 in → 43/4 in


A) Volume = 2/1 in * 16/3 in * 43/4 in = 2*16*43 / 1*3*4 = 1,376 in³ / 12 = 114.67 in³

B) 8 servings

114.67 in³ / 8 servings = 14.33 in³ per serving

Each serving occupies a volume of 14.33 in³ in the box of cereals. 

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Answer:

A

Step-by-step explanation:

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\displaystyle f(x) = \left\{        \begin{array}{ll}            2\cos(\pi x) \text{ for }  x \leq -1 \\ \\          \displaystyle   \frac{2}{\cos(\pi x)}\text{ for } x > -1        \end{array}    \right.

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So, we need to determine whether or not the limit exists. In other words, we will find the two one-sided limits.

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Since we are approaching from the left, we will use the first equation:

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By direct substitution:

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Right-Hand Limit:

\displaystyle \lim_{x\to -1^+}f(x)

Since we are approaching from the right, we will use the second equation:

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Direct substitution:

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So, we can see that:

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Since both the left- and right-hand limits exist and equal the same thing, we can conclude that:

\displaystyle \lim_{x \to -1}f(x)=-2

Our answer is A.

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f6odo6d7pfp7dp6d6p

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