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3 years ago

-4(5k-7)-2k=-2(9k+5)

1 answer:

5 0

If you distribute -4 through (5k-7), it equals -20k + 28. Then put on the other -2k on that side of the equals sign and you should have -22k + 28 = -2(9k+5) Then you need to distribute -2 through (9k+5) which equals -18k - 10. You then should have -22k+28=-18k-10. Add 22k to both sides to cancel it out, then you should have 28=4k-10. Add 10 to both sides to get the 4k by itself, which will be 38=4k, then divide both sides by 4 to get k by itself. 38/4 = 19/2. k = 19/2

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For questions 5 and 6, solve the system using the Elimination method.

beks73 [17]

Answer:

$\boxed{x = 7~~and~~y = -3}$

Step-by-step explanation:

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6x + 7y = 21 (times 5) 30x + 35y = 105

30x + 18y = 156

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$y = \frac{51}{-17}$

y = -3

Substitute the value of y to one of equations

6x + 7y = 21

6x + 7(-3) = 21

6x - 21 = 21

6x = 21 + 21

6x = 42

$x = \frac{42}{6}$

x = 7

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3 years ago

F(x) = -7x^2+8x+2 what is the value of the discriminant of f

Murrr4er [49]

Answer:

D = 120, there are 2 real roots for F(x)

Step-by-step explanatU

using the

formula D = b^2 - 4ac for discriminant

D = 8^2 - 4*(-7)*2

D = 64 + 56 = 120

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3 years ago

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The following pattern starts with 4 and uses the rule add 6 to the previous term.

Harrizon [31]

Answer:

Every number in the pattern is greater than the previous number.

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3 years ago

Find 2 consecutive even integers such that twice the larger integer is four more than half of the smaller integer

solong [7]

Answer:

0 and 2

Step-by-step explanation:

Let the two consecutive integers be 2x and 2x+2

We are given that twice the larger integer is four more than half of the smaller integer

$2(2x+2)=\frac{1}{2}(2x)+4$

$4x+4=x+4$

$x=0$

So, Two consecutive integers are 2(0)=0 and 2(0)+2=2

Hence the two consecutive integers are 0 and 2

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Step-by-step explanation:

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