Answer: or
Step-by-step explanation:
For this exercise you can convert the mixed number to an improper fraction:
1. Multiply the whole number part by the denominator of the fraction.
2. Add the product obtained and the numerator of the fraction (This will be the new numerator).
3. The denominator does not change.
Then:
You know that he had 30 minutes in time-out, he counted spots on the ceiling for minutes and the rest of the time he made faces at his stuffed tiger.
Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and minutes:
or
240is the answer for the question 16
Answer:
(1) Commutative property
(2) Distributive property/Definition of addition
(3) Compatibility with addition/Existence of additive inverse/Modulative property
(4) Compatibility with multiplication/Associative property/Definition of division/Existence of additive inverse/Commutative and modulative properties/Result
Step-by-step explanation:
We proceed to solve algebraically and explain each step:
1) GIven
2) Commutative property
3) Distributive property/Definition of addition
4) Definition of addition
5) Compatibility with addition
6) Existence of additive inverse/Modulative property
7) Compatibility with multiplication
8) Associative property/Definition of division/Existence of additive inverse/Commutative and modulative properties/Result
Hence, we have the following answers:
(1) Commutative property
(2) Distributive property/Definition of addition
(3) Compatibility with addition/Existence of additive inverse/Modulative property
(4) Compatibility with multiplication/Associative property/Definition of division/Existence of additive inverse/Commutative and modulative properties/Result
Answer: A) segment MN ≡ segment QPIf two triangles are congruent, they have corresponding sides and corresponding angles congruent.
In order to find which are the corresponding sides, you need to be careful about the order of the letters, and therefore of the vertices (see picture attached).
From the congruency, we can say:
∠M ≡ ∠P
∠N ≡ ∠Q (statement B)
∠O ≡ ∠R (statement D)
MN ≡ PQ
NO ≡ QR (statement C)
OM ≡ RP
Hence, the only statement which is not true is <span>
A) segment MN ≡ segment QP.</span>