Answer:
Explanation:
The first one is Prostista: Since they are mostly unicellular and are classified as eukaryotic.
The second one is Eubacteria: Since all Eubacteria has peptidoglycan in their cell walls.
The Last One is Achaebacteria: They tend to help in digestion which is a very acidic environment and fit the other two criteria
Cellular respiration uses oxygen to release the energy stored in food.
Explanation:
In breathing living organisms take oxygen and release the carbon dioxide it is similar to the aerobic respiration.
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide!
Answer and Explanation:
<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee
We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:
1) aa x AA
F1) 4/4=1 Aa
2) Bb x bb
F1) ½ bb
½ Bb
3) dd x Dd
F1) ½ dd
½ Dd
4) Ee x Ee
F1) ¼ EE
2/4 = ½ Ee
¼ ee
So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:
1 Aa x ½ Bb x ½ Dd x ½ Ee = 1/8 AaBbDdEe
1) The first stage of mitosis is actually just the condensing of the chromosomes.
2)They start out as double, then gradually get to the same number.
3)Cell actually spend the most time in the G phase of the cell cycle.
