G(x)=6(2)x+7+4 i think that is it
728x^2y^3 hope this helps
The surface area of triangular prism is 117.12 mm²
<u>Explanation:</u>
Base side, a = 9 mm
Base side, b = 6.6 mm
Base side, c = 5.2 mm
Height, h = 4 mm
Total surface area = ?
We know,
Surface area, A = 2 Ab ( a+b+c) h
Ab = √s(s-a) (s-b) (s-c)
s = a+b+c/2
Solving for A
A = ah + b h + ch + 1/2 √ -a⁴ + 2(ab)² + 2(ac)² - b⁴ + 2 (b c)² - c⁴
A = 9.4 + 6.6 X 4 + 5.2 X 4 + 1//2 √ -9⁴ + 2(9 X 6.6)² + 2(9 X 5.2)² - (6.6)⁴ + 2 (6.6 X 5.2)² - (5.2)⁴
A = 117.12 mm²
Therefore, the surface area of triangular prism is 117.12 mm²
Answer:
AD = 1/4AC
Step-by-step explanation:
Given that,
D is the the midpoint of AB
Therefore
AB = AD + DB
Since, D is the midpoint of the AB, therefore AD = DB
AB = AD + AD
AB = 2AD (i)
Similarly, B is the midpoint of AC
Hence,
AC = AB + BC
AC = AB + AB (because B is the midpoint)
AC = 2AB (ii)
By putting the value of AB from equation i to equation ii, we get
AC = 2(2AD)
AC = 4AD
AC/4 = AD
AD = 1/4AC
