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tatiyna
3 years ago
14

Let f(x)=6(2)x−1+4

Mathematics
1 answer:
atroni [7]3 years ago
5 0
G(x)=6(2)x+7+4 i think that is it

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Classify a triangle with vertices A(1, 1), B(4, 7), and C(7, 1) as one of the following.
mash [69]
B. Isosceles.  that is the correct answer
3 0
3 years ago
An observer in tower A sees a boat 1538 yd away at an angle of depression of 35°. To the nearest yard, how far is the boat away
Thepotemich [5.8K]
From my own solution, my answer is closest to D<span>. 1951 yd; 27°
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>

Pls. see my attachment. 

In it I divided the big triangle into two small right triangles. 
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite

From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.

I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle. 

Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.

With regards to the angle of depression, I used this formula:

tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>

</span>

8 0
3 years ago
Can't figure it out!!
Zanzabum
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\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying&#10;\\\\\\&#10;2b^2-4b-10b+20=0\implies 2b^2-14b+20=0&#10;\\\\\\&#10;b^2-7b+10=0\implies &#10;(b-2)(b-5)=0\implies b=&#10;\begin{cases}&#10;\boxed{5}\\&#10;2&#10;\end{cases}
8 0
3 years ago
Use PEMDAS to solve this problem <br><br> 6÷2(1+2)=?
Finger [1]
The answer would be 8. hope this helps
8 0
3 years ago
Read 2 more answers
A boat is heading towards a lighthouse, whose beacon-light is 136 feet above the
alexandr1967 [171]

The distance between the points A to B is 899.9 feet. After rounding off the  nearest integer we get 900 feet as the final answer.

Given we know that CD is perpendicular to AD.

The distance between CD is 139 feet.

As from points A the boat's crew measure the angle of elevation to the beacon as 6°

therefore, m∠A = 6°

Another time the angle of elevation is measured from point B which is 19°.

therefore, m∠DBC = 19°

tan 19° = CD/BD

BD = CD/tan19°

BD = 136/tan 19°

now for tan 6° = CD/AD (tangent is opposite over adjacent)

AD = CD/tan 6°

AD = 136/tan 6°

AB = AD ₋ BD

AB = 136/tan 6° ₋ 136/tan 19°

AB = 1295.2 ₋ 395.3

AB = 900 feet

hence the distance from point A to B is 900 feet.

Learn more about Heights and distances here:

brainly.com/question/2004882

#SPJ9

5 0
2 years ago
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