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3 years ago

Let f(x)=6(2)x−1+4

Mathematics

1 answer:

atroni [7]3 years ago

5 0

G(x)=6(2)x+7+4 i think that is it

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What is the value of x?

Angelina_Jolie [31]

Answer:

x = 5.4

Step-by-step explanation:

3/x = 4/7.2

cross-multiply:

4x = 21.6

x = 5.4

5 0

3 years ago

PLEASE IM DESPERATE<br> BRAINLIEST+THANKS***

Sloan [31]

ANSWER

Option B

and

Option D.

EXPLANATION

The graph of the function has an amplitude of 2 and a period of

$\frac{2\pi}{3}$

Choose all the equation that has an amplitude of 2 and a period of

$\frac{2\pi}{3}$

These are:

$y = 2 \sin3(x - \frac{2\pi}{3} )$

and

$y = 2 \sin(3x)$

The second and the last options are correct.

3 0

2 years ago

Read 2 more answers

What is the solution to<br><br>- 4x + 28 > 12

raketka [301]

Answer:

$\large\boxed{x$

Step-by-step explanation:

$-4x+28>12\qquad\text{subtract 28 from both sides}\\\\-4x>-16\qquad\text{change the signs}\\\\4x$

6 0

3 years ago

The rectangular prism is to be sliced perpendicular to the shaded face and is to pass through point B, parallel to the front fac

Natasha_Volkova [10]

Answer:

the answer is c i took the quiz

Step-by-step explanation:

5 0

3 years ago

Use the model below to estimate the average annual growth rate of a certain country's population for 1950, 1988, and 2010, where

Morgarella [4.7K]

Answer:

The average annual growth rate of a certain country's population for 1950, 1988, and 2010 are 2.398, 0.9985 and 0.2236 respectively.

Step-by-step explanation:

The given equation is

$Y=-0.0000084x^3+0.00211x^2-0.205x+8.423$

Where Y is the annual growth rate of a certain country's population and x is the number of years after 1900.

Difference between 1950 and 1900 is 50.

Put x=50 in the given equation.

$Y=-0.0000084(50)^3+0.00211(50)^2-0.205(50)+8.423$

$Y=2.398$

Therefore the estimated average annual growth rate of the country's population for 1950 is 2.398.

Difference between 1988 and 1900 is 88.

Put x=88 in the given equation.

$Y=-0.0000084(88)^3+0.00211(88)^2-0.205(88)+8.423$

$Y=0.9984752\approx 0.9985$

Therefore the estimated average annual growth rate of the country's population for 1988 is 0.9985.

Difference between 2010 and 1900 is 110.

Put x=110 in the given equation.

$Y=-0.0000084(110)^3+0.00211(110)^2-0.205(110)+8.423$

$Y=0.2236$

Therefore the estimated average annual growth rate of the country's population for 2010 is 0.2236.

8 0

3 years ago