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Svetach [21]
3 years ago
15

What is the equation of a line that passes through point r(−4, −3) and has a slope of 7?

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0
Slope m= 7
From general equation of a line;
y=mx+c
y=7x+c

Finding value of c by replacing for;
y=-3
x=-4
-3=7*(-4)+c
-3=-28+c
c=25
y=7x+25
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Brandie lives on the twelfth floor of her apartment building. She walks down 2 flights to visit a friend, then up 3 flights to d
Debora [2.8K]

Answer:

-1

Step-by-step explanation:

She walked down 2 flights, then up 3 flights. This would cause her to be 1 floor above her floor. So, she would have to walk down 1 flight (hence the negative in the -1) and she would be on her floor.

3 0
2 years ago
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5.401×10 <br> −1 as a standard form.
zvonat [6]

A negative exponent means to move the decimal point to the left the number of the exponent.

10^-1 you would move the decimal 1 place to the left.

5.401 x 10^-1 = 0.5401

4 0
3 years ago
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The cost of 90 kg of rice is 4500. what is the cost of 2 quintal of rice?​
gayaneshka [121]

Answer:

The cost of 2 quintal of rice is $10,000.

Step-by-step explanation:

To determine the cost of 2 quintals of rice, knowing that 90 kilos of said product is worth $ 4,500, it is first necessary to establish the equivalence between quintals and kilograms. In this regard, a quintal is equivalent to 100 kilograms, so 2 quintals are equivalent to 200 kilos.

Now, to determine the cost per kilogram of rice, the following calculation is required:

4,500 / 90 = X

50 = X

Therefore, 1 kilogram of rice costs $ 50. Thus, since 200 x 50 equals 10,000, 2 quintals of rice will cost $ 10,000.

5 0
3 years ago
Please explain how to find the answer for this
FromTheMoon [43]
P(A \textrm{ and } B) = P(A) P(B|A)

P(A \textrm{ and } B) = \dfrac{3}{10} \cdot \dfrac{2}{5} = \dfrac{3}{25}

Second to last choice.


5 0
3 years ago
What is m∠KNL? Enter your answer in the box. ° A horizontal line segment M K intersects with line segment J L at their midpoint
inna [77]

t N.

In the figure shown below

Answer:

A horizontal line segment M K intersects with line segment J L at their midpoint N.

∠J N M =(5x+2)°

∠ LN M=3( x+ 14)°

So, ∠J N M + ∠ LN M =180°[ These two angles form linear pair.Angles forming linear pair are supplementary.]

⇒5 x+ 2+ 3 (x+ 14) =180 [ By Substitution]

⇒ 5 x+2 +3 x+42°= 180°

⇒ 8 x=180°-44°

⇒8 x= 136°

⇒x= 136°÷8

⇒x=17°

So, ∠J N M =5×17 +2=87°

∠ LN M= 3×(17 +14)=3×31=93

∠J N M =∠K N L [Vertically opposite angles]

∠K N L=87°


8 0
3 years ago
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