All categories

3 years ago

Which expression can be used to fine the slope of a line containing the points (-3,2) and (7,-1)

Mathematics

1 answer:

Charra [1.4K]3 years ago

7 0

Hello there! you can use the expression $\frac{ y_{1}-y_{2}}{x_{1}-x_{2} }$ !

To find slope, subtract the y values over the x values.

In this case:

2 - - 1 / - 3 - 7

3 / -10

So, -3/10 would be the slope of these points.

Hope this helps, have a great day!

You might be interested in

Determine if true or false

s2008m [1.1K]

True because every element ofset a

6 0

3 years ago

Read 2 more answers

What is 3.47 correct to 2 decimal places what is 8.132 correct to 3 decimal places

Olenka [21]

If I'm understanding the question they should be those. If you want to go left then the would be

Left
0.00347
0.008132

Right
347.
8,132.

6 0

3 years ago

Which of the following quartic functions has x=-1 and x=-2 as its only two real zeros

Brums [2.3K]

Quartic is 4th degree
the factors of an equation with roots r1,r2 is
(x-r1)(x-r2)
4th degree
it could be
(x-r1)¹(x-r2)³ or
(x-r1)²(x-r2)² or
(x-r1)³(x-r2)¹

roots or zeroes at x=-1 and x=-2
(x-(-1)) and (x-(-2))
(x+1) and (x+2)

the function could be factored into
(x+1)¹(x+2)³ or
(x+1)²(x+2)² or
(x+1)³(x+2)¹

expanded would be
x⁴+7x³+18x²+20x+9 or
x⁴+6x³+13x²+12x+4 or
x⁴+5x³+9x²+7x+2
one of those is the answer

4 0

3 years ago

Which is smaller: 5 nanometers or 50 micrometers

lina2011 [118]

5 nanometers is smaller

8 0

3 years ago

Read 2 more answers

Douglas invests money in two simple interest accounts. He invests three times as much in an account paying 14% as he does in an

Rainbow [258]

Douglas invested $ 1300 altogether

Solution:

Let x represent the amount invested in the account paying 14% interest.

Let y represent the amount invested in the account paying 5% interest

He invests three times as much in an account paying 14% as he does in an account paying 5%

Which means,

x = 3y

The simple interest is given by formula:

$S.I = \frac{p \times n \times r}{100}$

Where,

"p" is the principal

"n" is the number of years

"r" is the rate of interest

He earns $152.75 in interest in one year from both accounts combined

Therefore,

Combined S.I = 152.75

n = 1 year

Considering the account earning 14% interest:

$S.I = \frac{3y \times 14 \times 1}{100}\\\\S.I = 0.42y$

Considering the account earning 5% interest:

$S.I = \frac{y \times 5 \times 1}{100}\\\\S.I = 0.05y$

Since, Combined S.I = 152.75

Therefore,

0.42y + 0.05y = 152.75

0.47y = 152.75

Divide both sides by 0.47

y = 325

Therefore,

x = 3y

x = 3(325)

x = 975

how much did he invest altogether?

Amount invested together = x + y = 975 + 325 = 1300

Thus he invested $ 1300 altogether

3 0

3 years ago