Answer:
P____Q____R
PR= PQ+ QR
(14x-13) = (5x-2)+(6x+1)
14x-13= 11x – 1
14x – 11x = 13–1
3x = 12
x= 12/ 3
x= 4
PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5
If you want (PQ , QR ) this is the solution
PQ =5x-2=5(4)-2=20-2=18
QR =6x+1=6(4)+1=24+1=25
I hope I helped you^_^
Answer:
h = 9 units of length
Step-by-step explanation:
Volume of a circular right cone is:
V(c) = (1/3)*Area of the circular base * h
Where h is the height of the cone, then
V(c) = (1/3) * π * r² * h
And we have that V(c) = 108*π
Then:
108 * π = (1/3) * π * r² * h (1)
We know diameter of the circular base is 12 units, according to that
r = d/2 ⇒ r = 12/2 r = 6 units
Then:
108 * π [ cubic units ] = (1/3) * π * (6)² * h [square units] [ units of length]
When simplifying we have to take into account that in order to keep last equation h needs to have units of length
Therefore:
108 = (1/3) * 36 * h
h = ( 108* 3 )/ 36
h = 9 units of length
For this case we have the following functions:
m (x)
p (x)
Where,
x: independent variable
m, p: dependent variables
For the value of x = 7 we have:
m (7)
p (7)
For this case it is true that:
m (7) = p (7)
Therefore, both functions have the same output argument for the same input value.
Answer:
C) Both m (x) and p (x) have the same output value at x = 7.
Answer:
x = 8
Step-by-step explanation:
4x + 3 = 35
subtract 3 from both sides
4x + 3 - 3 = 35 - 4
4x = 32
divide both sides by 4
4x / 4 = x
32/4 = 8
we're left with x = 8
