To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,

Therefore, 500 gallons of 80% antifreeze solution is required.
-8-4y=-5x
-4y=-5x+8
y=5/4x+2
slope= 5/4
y-intercept=(0,2)
2 x -6 equals 0. add 6 to both sides. divide both sides by two. x equals 3
Answer:
Step-by-step explanation:
<h2>7 but th 3rd is silrt</h2>
7435 divided by 5 equals 1487