The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.
<h3>What is the book value at the end of year 2? </h3>
Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.
Sum-of-the-year digits = (remaining useful life / sum of the years ) x (Cost of asset - Salvage value)
Depreciation expense in year 1:
Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210
Undepreciated life of the asset = 20
(20 / 210) x ($79,600 - 4,000) = 7200
Depreciation expense in year 2:
19 / 210 x ($79,600 - 4,000) = 6840
Book value = 79600 - 7200 - 6840 = $65,560
To learn more about depreciation, please check: brainly.com/question/25552427
If I understood the question correctly, the answer would be 400
Answer:
Combine the terms
300 + 70 = 370
5/10 + 8/100
Note that first, you must find common denominators. What you multiply to the denominator, you multiply to the numerator. Multiply 10 to the numerator and denominator of 5/10
(5/10)(10/10) = 50/100
50/100 + 8/100
Combine the terms
50/100 + 8/100 = 58/100
370 58/100 is another way to write it
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
20
Step-by-step explanation:
Use <u>PEMDAS</u>
P = parenthesis
E = Exponents
M = Multiplication*
D = Division*
A = Addition**
S = Subtraction**
*either can come first, it just depends which comes first in the equation.
**either can come first, it just depends which comes first in the equation.
<em>Step 1 : Write equation</em> 4( 9 × 2 ) ÷ ( 4 -1 ) - 4
<em>Step 2: Solve in parenthesis </em>4(18) ÷ (3) - 4
<em>Step 3: Solve multiplication </em> 72 ÷ 3 - 4
<em>Step 4: Solve division </em>24 - 4
<em>Step 5 : Solve subtraction</em> 20
