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SashulF [63]
3 years ago
13

A convention planner estimates that the size in square feet of a room needed for a large assembly is 20 times the number of atte

ndees if the planner estimates that 200 people will attend what minimum size room ( in square feet) is required ?
Mathematics
1 answer:
enot [183]3 years ago
4 0

Answer:

4000 Sq feet.

Step-by-step explanation:

Since the room needed is 20 times the number of attendees and 200 attendees are expected to come, it's just 20x200. Looking for keywords such as times really help!

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y = mx + b

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y = 2x + 5

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A metallurgist needs to make 12.4 lb. of an 10) alloy containing 50% gold. He is going to melt and combine one metal that is 60%
sergeinik [125]
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likewise, if we use "y" lbs of the 40% alloy, how much gold is in it?  well, 40% of y, or (40/100) * y, or 0.4y.

now, whatever "x" and "y" are, their sum must be 12.4 lbs.

we also know that the gold amount in each added up, must equal that of the 50% resulting alloy.

\bf \begin{array}{lccclll}&#10;&\stackrel{lbs}{amount}&\stackrel{gold~\%}{quantity}&\stackrel{gold}{quantity}\\&#10;&------&------&------\\&#10;\textit{60\% alloy}&x&0.6&0.6x\\&#10;\textit{40\% alloy}&y&0.4&0.4y\\&#10;------&------&------&------\\&#10;\textit{50\% alloy}&12.4&0.50&6.2&#10;\end{array}

\bf \begin{cases}&#10;x+y=12.4\implies \boxed{y}=12.4-x\\&#10;0.6x+0.4y=6.2\\&#10;-------------\\&#10;0.6x+0.4\left( \boxed{12.4-x} \right)=6.2&#10;\end{cases}&#10;\\\\\\&#10;0.6x-0.4x+4.96=6.2\implies 0.2x=1.24\implies x=\cfrac{1.24}{0.2}&#10;\\\\\\&#10;x=\stackrel{lbs}{6.2}

how much of the 40% alloy?  well, y = 12.4 - x.
5 0
4 years ago
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4 years ago
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The answer will be that they'll be on the 47 yard line on the next play.

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Step-by-step explanation:

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