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3 years ago

URGENT! PLEASE HELP NOW!

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

8 0

The sum is 34 and the add and multiemployer

Valentin [98]3 years ago

5 0

Jasmine is 23 years old. Three years less, 20, half is 10. If I am correct, George is 10.

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What is equivalent form of the expression 15x + 24ax

neonofarm [45]

15x + 24ax = 3x(5+8a)

3 0

3 years ago

Hey! Please find the value of x, so I can find the value of angle H! Thanks

o-na [289]

Hey there! :D

The congruence marks on the trapezoid make the angles congruent. This makes opposite angles supplementary. (Because all the angles in a trapezoid add up to 360 degrees)

12x-31+6x-5= 180

18x-36= 180

Add 36 to both sides.

18x= 216

Divide both sides by 18.

x= 12

You can just plug that in to find m<H.

6x-5

6(12)-5

72-5

m<H= 67

I hope this helps!
~kaikers

3 0

3 years ago

Please help!!! Mark is learning to snowboard. The club charges $10 per hour for snowboard lessons and $40 for the lift ticket an

sveta [45]

H represents the number of hours:
10h + 40
(40 represents, well $40)

4 0

3 years ago

Read 2 more answers

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

6 0

3 years ago

Determine whether the two expressions are equivalent. If so, tell what property is applied.

Hoochie [10]

Answer:

I think its associative property but I am not sure.

Step-by-step explanation:

4 0

3 years ago