<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
Answer:
Let's simplify step-by-step.
14xy+3xy+2x(y−17)
=19xy−34x
The mean is 0.0118 approximately. So option C is correct
<h3><u>Solution:</u></h3>
Given that , The probability of winning a certain lottery is
for people who play 908 times
We have to find the mean number of wins

Assume that a procedure yields a binomial distribution with a trial repeated n times.
Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.



Hence, the mean is 0.0118 approximately. So option C is correct.