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1 year ago

What is the reason that 2 points always determine a line

Mathematics

1 answer:

Zanzabum1 year ago

4 0

Answer:

Because the line is the shortest path between 2 points

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Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form

raketka [301]

Answer:

y-3= 2(x-1)

Step-by-step explanation:

1. The equation of a line in point slope form is y-y1= m(x-x1)

2. m=slope and (x1,y1) is the point the line passes through

3. The point the line passes through is (1,3)

4, The slope is 2

5. Therefore the answer is y-3=2(x-1)

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2 years ago

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*****ANSWER FAST*****<br> I’LL GIVE BRAINIEST

Makovka662 [10]

3rd quartile is different, minimum is same, median is same, IQR is can't tell, mode is same,and mean is different

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2 years ago

A business man invested 10,500 in a company and the value increases 3.5% each year. How much will be the investment after 12 yea

alekssr [168]

Answer:

441,000 dollars after 12 years

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2 years ago

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The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

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2 years ago

Find the decimal equivelent to 2/11 what kind of decimal is it

kolbaska11 [484]

Answer:

Simply divide the numerator by the denominator:

= 2/11

= 2 ÷ 11

= 0.18181818181818

pls mark me as the brainliest

8 0

3 years ago