PLEASE HELP AM SO DESPERATE FOR HELP
1 answer:
Answer:
15. a 7.9 miles
b. NO .
Step-by-step explanation:
From the table, on
Monday = 3 2/5
Wednesday = 4 1/2
Write the distance in improper fractions as;
Monday = 17/5
Wednesday = 9/2
Find the sum as
where the L.C.M is 10
Answer is 7.9 miles
b.
Distance covered on Thursday and Saturday will be
2 2/6 + 3 3/4
14/6 + 15/4 ------the L.C.M is 12
(28+45)/12
73/12
The distance 73/12 miles for Thursday + Saturday is less than that of Monday + Wednesday 79/10 miles. The answer is NO.
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I know this is old question but i'd like to solve it :)
Integrate both sides with respect to <em>t</em> :
∫ d<em>y</em>/d<em>t</em> d<em>t</em> = ∫ -12<em>t</em> ² d<em>t</em>
<em>y(t)</em> = -4<em>t</em> ³ + <em>C</em>
Use the initial condition to solve for <em>C</em> :
5 = -4•0³+ <em>C</em>
<em>C</em> = 5
So
<em>y(t)</em> = -4<em>t</em> ³ + 5
and the answer is D.
Alternatively, you can directly apply the fundamental theorem of calculus: