<em>parallelogram</em>
1. perimeter 10(2)+10(2)=32+20
perimeter = 52cm
area=b times h
area = 16(9)=144cm2
2 <em>TRAPEZOID</em>
<em> </em>perimeter =( 21+24+25+44.67)m
=114.67m
area= 1/2( b1+b2)h
1/2(44.67+25)20
696.7m2
3. perimeter = 2+3+12+2+3+5+3+2+9+7+3
=51<u>cm</u>
area = 54+6+6+6=72cm2<u> </u>
4. perimeter is 10+4+2+3+ 2+4+10+23 = <u>58cm</u>
<u>area is </u>
(11+23).8=37.8
=272
trap-rect=136-6
<em>=130ft2</em>
Answer:
Step-by-step explanation:
Given that:
the perimeter of the fencing (rectangle) = 200
Let recall that the area equation of a rectangle = L × w
The perimeter now = 2(L + w)
The perimeter = 2L + 2w
∴
200 = 2L +2w
Dividing both sides by 2
100 = L + w
Making Length L the subject; we have:
- L = -100 + w
L = 100 - w
Thus;
A(w) = (100 - w) w
and the domain of the function is (0,100)
Answer:
Step-by-step explanation: Sub -3 into where all the u’s are. So it would be
(-3)^2 - 2(-3) + 4
Which would equal 19
Answer:
m equals √16, n= 3 1/2
Step-by-step explanation:
the one from the top right
