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3 years ago

Help me pleaseee !!! I'll give brainliest!!

Mathematics

2 answers:

Bad White [126]3 years ago

6 0

Im just getting points sorry

Ksju [112]3 years ago

4 0

A) vertex: (0,3)
b) axis of symmetry: x=0
c) y-intercept: (0,3)
d) x-intercept: none
e) minimum: (0,3)
f) a is positive because the graph is above the x-axis

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Jenna constructs the model to represent 3x2 + 11x – 4. An algebra tile configuration. 0 tiles are in the Factor 1 spot. 0 tiles

makvit [3.9K]

Answer:

the answer is the 2nd one (3x-1) and (x+4)

Step-by-step explanation:

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4 years ago

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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is . What is the standard form of the

kvasek [131]

Answer:

Point-Slope form: $y+1=-\frac{6}{15}(x+5)\\$

standard form: $2x+5y=-15$

Step-by-step explanation:

The standard form is given by: $Ax+By=C$

The point-slope form is given by: $y-y_1=m(x-x_1)$

Let's call $(-5,-1)$ as point $(x_1,y_1)$ , and

point $(10,-7)$ as point $(x_2,y_2)$

We also know that the slope $m$ is given by $m=\frac{y_2-y_1}{x_2-x_1}$

Let's find the slope:

$m=\frac{-7-(-1)}{10-(-5)}=-\frac{6}{15}$

1. So, point slope form can be written as:

$y-(-1)=-\frac{6}{15}(x-(-5))\\y+1=-\frac{6}{15}(x+5)\\$

2. Rearranging this equation and bringing all x's and y's to one side and the number to another side will give us the standard form. So:

$y+1=-\frac{6}{15}x-2\\y+\frac{6}{15}x=-2-1\\y+\frac{6}{15}x=-3$

But A, B, and C (standard form) needs to be integers, so to get rid of the denominator , we multiply the whole equation by 15. So we have:

$y+\frac{6}{15}x=-3\\15y+6x=-45$

We can factor out a 3, so it becomes:

$15y+6x=-45\\5y+2x=-15$

So standard form is $2x+5y=-15$

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4 years ago

Bass Pro has a sale on boats! Just what you have always wanted and it is $3000 cheaper than it usually

seraphim [82]

Answer:

$4500

Step-by-step explanation:

$350 x 10 = 3500 + 1000 which ends up with a total of $4500. I hope this helped :)

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4 years ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

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3 years ago

What can 6 be divided by to = 4

asambeis [7]

Answer:

By 24

Step-by-step explanation:

First, you have to try dividing by a number that 4 and 6 can be multiplied by.

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3 years ago

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