Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
Answer:
- 1/12
Step-by-step explanation:
Let -0.0833333 = x --- (1)
Multiply both sides by 10.
-0.833333 = 10x --- (2)
Subtract (2) from (1),
0.75 = -9x
-9x = 
= 


Answer:
9x,2,8y
Step-by-step explanation: