Answer:
no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
Step-by-step explanation:
Let the no of 2kg disks be a.
Let no of 5 kg disks be b.
2a+5b=29
a+b=10
Using substitution, we have
2(10-b) + 5b=29
20-2b+5b=29
20+3b=29
3b=9
b=3
So no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
Answer:
21
Step-by-step explanation:
The first problem, all you need to do is combine like terms then isolate the n:
4n-2n=4
~subtract 2n from 4n (2n)
2n=4
~then divide both sides of the equation by 2 to isolate the n
n=4
The second problem follows the same steps of combining like terms and isolating the variable. Here, you'll have to combine 2 like terms:
-12=2+5v+2v
~first combine the variables which is just 5v+2v which is 7v
-12=2+7v
~then subtract 2 from both sides to isolate the 7v
-14=7v
~then divide both sides by 7 to isolate the v and get your answer
-2=v
Hope that helped!
Answer: F (False)
Step-by-step explanation:
Jointly variation has the following form:
y=kxz
Where k is a constant of propotionality.
Substitute values:
If y=16, x=4 and z=2, then k is:
If x=-8 and z=-3 the the value of y is:
Then the answer is FALSE.
