Question

(3rt^2)^2 (9rs^2t^3)^-2

Answer 1

$( {3}^{2} {r}^{2} {t}^{4} )( \frac{1}{ {9}^{2} {r}^{2} {s}^{4} {t}^{6} } )$
$\frac{1}{9 {s}^{4} {t}^{2} }$